Snooker - Ding overcomes Robertson in India

Ding Junhui continued his quest for Indian Open glory with a 4-2 win over world number one Neil Robertson.

Eurosport
Snooker - Ding progresses to Indian Open final
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Ding Junhui (Imago)

Ding will face Robbie Williams in the last four on Friday after he completed a 4-0 win over Anthony McGill.

Stephen Maguire was a 4-3 winner over Michael White while Aditya Mehta won the 'Indian derby' with a 4-3 victory over Pankaaj Advani.

QUARTER FINALS

NEIL ROBERTSON 2-4 DING JUNHUI

ANTHONY MCGILL 0-4 ROBBIE WILLIAMS . .

MICHAEL WHITE 3-4 STEPHEN MAGUIRE . .

PANKAJ ADVANI 3-4 ADITYA MEHTA

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